10p^2=-11p+6

Solution for 10p^2=-11p+6 equation:

10p^2=-11p+6

We move all terms to the left:

10p^2-(-11p+6)=0

We get rid of parentheses

10p^2+11p-6=0

a = 10; b = 11; c = -6;
Δ = b2-4ac
Δ = 112-4·10·(-6)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-19}{2*10}=\frac{-30}{20}
=-1+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+19}{2*10}=\frac{8}{20}
=2/5
$